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4x^2-54x+72=0
a = 4; b = -54; c = +72;
Δ = b2-4ac
Δ = -542-4·4·72
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-42}{2*4}=\frac{12}{8} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+42}{2*4}=\frac{96}{8} =12 $
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